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# Maths: Decimal Fraction Questions for SBI, IBPS, SSC

Decimal Fraction Questions: A lot of questions are asked on Decimal Fraction in various competitive exams such as SBI, IBPS PO and Clerk, SSC CGL, CHSL, Railways, other exams. If you prepare this topic thoroughly, you can score good marks in maths section. Candidates can attempt questions given below and ask doubts in comment section. Click here to join whatsapp/telegram study group

## Decimal Fraction Questions

Q) Evaluate : [{(2.39)2 – (1.61)2} / (2.39 – 1.61)]
A. 2
B. 4
C. 6
D. 8

Explanation:
Given Expression = [(a2 – b2) / (a – b)] = [{(a + b)(a – b)} / (a – b)] = (a + b) = (2.39 + 1.61) = 4.

Q) What decimal of an hour is a second?
A. .0025
B. .0256
C. .00027
D. .000126

Explanation:
Required decimal = [1 / (60 * 60)] = (1/3600) = .00027

Q) If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
A. 0.172
B. 1.72
C. 17.2
D. 172

Explanation:
(29.94/1.45) = (299.4/14.5)
= [(2994/14.5) * (1/10)] [Here, Substitute 172 in the place of (2994/14.5)]
= (172/10) = 17.2

Q) (.009/?) = .01
A. .0009
B. .09
C. .9
D. 9

Explanation:
Let (.009/x) = .01;
Then, x = (.009/.01) = (.9/1) = .9

Q) The expression (11.98 * 11.98 + 11.98 * x + 0.02 * 0.02) will be a perfect square for x equal to:
A. 0.02
B. 0.2
C. 0.04
D. 0.4

Explanation:
Given expression = (11.98)2 + (0.02)2 + 11.98 * x.
For the given expression to be a perfect square, we must have
6.98 * x = 2 * 11.98 * 0.02
⇒ x = 0.04

Q) 3889 + 12.952 – ? = 3854.002
A. 47.095
B. 47.752
C. 47.932
D. 47.95

Explanation:
Let 3889 + 12.952 – x = 3854.002.
Then x = (3889 + 12.952) – 3854.002
= 3901.952 – 3854.002
= 47.95.

Q) 0.04 * 0.0162 is equal to:
A. 6.48 * 10-3
B. 6.48 * 10-4
C. 6.48 * 10-5
D. 6.48 * 10-6

Explanation:
4 * 162 = 648.
Sum of decimal places = 6.
So, 0.04 * 0.0162 = 0.000648 = 6.48 * 10-4

Q) [(4.2 * 4.2 – 1.9 * 1.9) / (2.3 * 6.1)] is equal to:
A. 0.5
B. 1.0
C. 20
D. 22

Explanation:
Given Expression = [(a2 – b2) / {(a + b)(a – b)}] = [(a2 – b2) / (a2 – b2)] = 1.

Q) If (144/0.144) = (14.4/x), then the value of x is:
A. 0.0144
B. 1.44
C. 14.4
D. 144

Explanation:
(144/0.144) = (14.4/x)
⇒ [(144 * 1000) / 144] = (14.4/x)
⇒ x = (14.4/1000) = 0.0144

Q) The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y?
A. 2010
B. 2011
C. 2012
D. 2013

Explanation:
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) – (6.30 + 0.15z) = 0.40
⇒ 0.25z = 0.40 + 2.10
⇒ z = (2.50/0.25) = (250/25) = 10.
.’. X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.

Q) Which of the following fractions is greater than (3/4) and less than (5/6)?
A. ½
B. 2/3
C. 4/5
D. 9/10

Explanation:
(3/4) = 0.75, (5/6) = 0.833, (1/2) = 0.5, (2/3) = 0.66, (4/5) = 0.8, (9/10) = 0.9.
Clearly, 0.8 lies between 0.75 and 0.833.
.’. (4/5) lies between (3/4) and (5/6).

Q) The value of [(489.1375 * 0.0483 * 1.956) / (0.0873 * 92.581 * 99.749)] is closest to:
A. 0.006
B. 0.06
C. 0.6
D. 6

Explanation:
[(489.1375 * 0.0483 * 1.956) / (0.0873 * 92.581 * 99.749)] ≈ [(489 * 0.05 * 2) / (0.09 * 93 * 100)]
= [489 / (9 * 93 * 10)] = (163/279) * (1/10) = (0.58/10) = 0.058 ≈ 0.06.

Q) 0.002 * 0.5 = ?
A. 0.0001
B. 0.001
C. 0.01
D. 0.1

Explanation:
2 * 5 = 10.
Sum of decimal places = 4
.’. 0.002 * 0.5 = 0.001

Q) Which of the following is equal to 3.14 x 106?
A. 314
B. 3140
C. 3140000
D. None of these

Explanation:
3.14 * 106 = 3.14 * 1000000 = 3140000.

Q) [{(5 * 1.6) – (2 * 1.4)} / 1.3] = ?
A. 0.4
B. 1.2
C. 1.4
D. 4

Explanation:
Given Expression = [(8 – 2.8) / 1.3] = (5.2/1.3) = (52/13) = 4.

Q) How many digits will be there to the right of the decimal point in the product of 95.75 and .02554?
A. 5
B. 6
C. 7
D. None of these

Explanation:
Sum of decimal places = 7.
Since the last digit to the extreme right will be zero (since 5 * 4 = 20), so there will be 6 significant digits to the right of the decimal point.

Q) The fraction 101(27/100000) in decimal for is:
A. .01027
B. .10127
C. 101.00027
D. 101.000027

Explanation:
101(27/100000) = [101 + (27/100000)] = 101 + .00027 = 101.00027

Q) [(0.0203 * 2.92) / (0.0073 * 14.5 * 0.7)] = ?
A. 0.8
B. 1.45
C. 2.40
D. 3.25

Explanation:
[(0.0203 * 2.92) / (0.0073 * 14.5 * 0.7)] = [(203 * 292) / (73 * 145 * 7)] = (4/5) = 0.8

Q) 4.036 divided by 0.04 gives:
A. 1.009
B. 10.09
C. 100.9
D. None of these